3x^2-18x+96=0

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Solution for 3x^2-18x+96=0 equation: 



3x^2-18x+96=0

a = 3; b = -18; c = +96;
Δ = b2-4ac
Δ = -182-4·3·96
Δ = -828
Delta is less than zero, so there is no solution for the equation

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